Integrand size = 17, antiderivative size = 198 \[ \int \frac {(c+d x)^{5/2}}{(a+b x)^6} \, dx=-\frac {d^2 \sqrt {c+d x}}{16 b^3 (a+b x)^3}-\frac {d^3 \sqrt {c+d x}}{64 b^3 (b c-a d) (a+b x)^2}+\frac {3 d^4 \sqrt {c+d x}}{128 b^3 (b c-a d)^2 (a+b x)}-\frac {d (c+d x)^{3/2}}{8 b^2 (a+b x)^4}-\frac {(c+d x)^{5/2}}{5 b (a+b x)^5}-\frac {3 d^5 \text {arctanh}\left (\frac {\sqrt {b} \sqrt {c+d x}}{\sqrt {b c-a d}}\right )}{128 b^{7/2} (b c-a d)^{5/2}} \]
[Out]
Time = 0.06 (sec) , antiderivative size = 198, normalized size of antiderivative = 1.00, number of steps used = 7, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.235, Rules used = {43, 44, 65, 214} \[ \int \frac {(c+d x)^{5/2}}{(a+b x)^6} \, dx=-\frac {3 d^5 \text {arctanh}\left (\frac {\sqrt {b} \sqrt {c+d x}}{\sqrt {b c-a d}}\right )}{128 b^{7/2} (b c-a d)^{5/2}}+\frac {3 d^4 \sqrt {c+d x}}{128 b^3 (a+b x) (b c-a d)^2}-\frac {d^3 \sqrt {c+d x}}{64 b^3 (a+b x)^2 (b c-a d)}-\frac {d^2 \sqrt {c+d x}}{16 b^3 (a+b x)^3}-\frac {d (c+d x)^{3/2}}{8 b^2 (a+b x)^4}-\frac {(c+d x)^{5/2}}{5 b (a+b x)^5} \]
[In]
[Out]
Rule 43
Rule 44
Rule 65
Rule 214
Rubi steps \begin{align*} \text {integral}& = -\frac {(c+d x)^{5/2}}{5 b (a+b x)^5}+\frac {d \int \frac {(c+d x)^{3/2}}{(a+b x)^5} \, dx}{2 b} \\ & = -\frac {d (c+d x)^{3/2}}{8 b^2 (a+b x)^4}-\frac {(c+d x)^{5/2}}{5 b (a+b x)^5}+\frac {\left (3 d^2\right ) \int \frac {\sqrt {c+d x}}{(a+b x)^4} \, dx}{16 b^2} \\ & = -\frac {d^2 \sqrt {c+d x}}{16 b^3 (a+b x)^3}-\frac {d (c+d x)^{3/2}}{8 b^2 (a+b x)^4}-\frac {(c+d x)^{5/2}}{5 b (a+b x)^5}+\frac {d^3 \int \frac {1}{(a+b x)^3 \sqrt {c+d x}} \, dx}{32 b^3} \\ & = -\frac {d^2 \sqrt {c+d x}}{16 b^3 (a+b x)^3}-\frac {d^3 \sqrt {c+d x}}{64 b^3 (b c-a d) (a+b x)^2}-\frac {d (c+d x)^{3/2}}{8 b^2 (a+b x)^4}-\frac {(c+d x)^{5/2}}{5 b (a+b x)^5}-\frac {\left (3 d^4\right ) \int \frac {1}{(a+b x)^2 \sqrt {c+d x}} \, dx}{128 b^3 (b c-a d)} \\ & = -\frac {d^2 \sqrt {c+d x}}{16 b^3 (a+b x)^3}-\frac {d^3 \sqrt {c+d x}}{64 b^3 (b c-a d) (a+b x)^2}+\frac {3 d^4 \sqrt {c+d x}}{128 b^3 (b c-a d)^2 (a+b x)}-\frac {d (c+d x)^{3/2}}{8 b^2 (a+b x)^4}-\frac {(c+d x)^{5/2}}{5 b (a+b x)^5}+\frac {\left (3 d^5\right ) \int \frac {1}{(a+b x) \sqrt {c+d x}} \, dx}{256 b^3 (b c-a d)^2} \\ & = -\frac {d^2 \sqrt {c+d x}}{16 b^3 (a+b x)^3}-\frac {d^3 \sqrt {c+d x}}{64 b^3 (b c-a d) (a+b x)^2}+\frac {3 d^4 \sqrt {c+d x}}{128 b^3 (b c-a d)^2 (a+b x)}-\frac {d (c+d x)^{3/2}}{8 b^2 (a+b x)^4}-\frac {(c+d x)^{5/2}}{5 b (a+b x)^5}+\frac {\left (3 d^4\right ) \text {Subst}\left (\int \frac {1}{a-\frac {b c}{d}+\frac {b x^2}{d}} \, dx,x,\sqrt {c+d x}\right )}{128 b^3 (b c-a d)^2} \\ & = -\frac {d^2 \sqrt {c+d x}}{16 b^3 (a+b x)^3}-\frac {d^3 \sqrt {c+d x}}{64 b^3 (b c-a d) (a+b x)^2}+\frac {3 d^4 \sqrt {c+d x}}{128 b^3 (b c-a d)^2 (a+b x)}-\frac {d (c+d x)^{3/2}}{8 b^2 (a+b x)^4}-\frac {(c+d x)^{5/2}}{5 b (a+b x)^5}-\frac {3 d^5 \tanh ^{-1}\left (\frac {\sqrt {b} \sqrt {c+d x}}{\sqrt {b c-a d}}\right )}{128 b^{7/2} (b c-a d)^{5/2}} \\ \end{align*}
Time = 1.16 (sec) , antiderivative size = 222, normalized size of antiderivative = 1.12 \[ \int \frac {(c+d x)^{5/2}}{(a+b x)^6} \, dx=-\frac {\sqrt {c+d x} \left (15 a^4 d^4+10 a^3 b d^3 (c+7 d x)+2 a^2 b^2 d^2 \left (4 c^2+23 c d x+64 d^2 x^2\right )-2 a b^3 d \left (88 c^3+256 c^2 d x+233 c d^2 x^2+35 d^3 x^3\right )+b^4 \left (128 c^4+336 c^3 d x+248 c^2 d^2 x^2+10 c d^3 x^3-15 d^4 x^4\right )\right )}{640 b^3 (b c-a d)^2 (a+b x)^5}+\frac {3 d^5 \arctan \left (\frac {\sqrt {b} \sqrt {c+d x}}{\sqrt {-b c+a d}}\right )}{128 b^{7/2} (-b c+a d)^{5/2}} \]
[In]
[Out]
Time = 0.56 (sec) , antiderivative size = 205, normalized size of antiderivative = 1.04
method | result | size |
derivativedivides | \(2 d^{5} \left (\frac {\frac {3 b \left (d x +c \right )^{\frac {9}{2}}}{256 \left (a^{2} d^{2}-2 a b c d +b^{2} c^{2}\right )}+\frac {7 \left (d x +c \right )^{\frac {7}{2}}}{128 \left (a d -b c \right )}-\frac {\left (d x +c \right )^{\frac {5}{2}}}{10 b}-\frac {7 \left (a d -b c \right ) \left (d x +c \right )^{\frac {3}{2}}}{128 b^{2}}-\frac {3 \left (a^{2} d^{2}-2 a b c d +b^{2} c^{2}\right ) \sqrt {d x +c}}{256 b^{3}}}{\left (\left (d x +c \right ) b +a d -b c \right )^{5}}+\frac {3 \arctan \left (\frac {b \sqrt {d x +c}}{\sqrt {\left (a d -b c \right ) b}}\right )}{256 b^{3} \left (a^{2} d^{2}-2 a b c d +b^{2} c^{2}\right ) \sqrt {\left (a d -b c \right ) b}}\right )\) | \(205\) |
default | \(2 d^{5} \left (\frac {\frac {3 b \left (d x +c \right )^{\frac {9}{2}}}{256 \left (a^{2} d^{2}-2 a b c d +b^{2} c^{2}\right )}+\frac {7 \left (d x +c \right )^{\frac {7}{2}}}{128 \left (a d -b c \right )}-\frac {\left (d x +c \right )^{\frac {5}{2}}}{10 b}-\frac {7 \left (a d -b c \right ) \left (d x +c \right )^{\frac {3}{2}}}{128 b^{2}}-\frac {3 \left (a^{2} d^{2}-2 a b c d +b^{2} c^{2}\right ) \sqrt {d x +c}}{256 b^{3}}}{\left (\left (d x +c \right ) b +a d -b c \right )^{5}}+\frac {3 \arctan \left (\frac {b \sqrt {d x +c}}{\sqrt {\left (a d -b c \right ) b}}\right )}{256 b^{3} \left (a^{2} d^{2}-2 a b c d +b^{2} c^{2}\right ) \sqrt {\left (a d -b c \right ) b}}\right )\) | \(205\) |
pseudoelliptic | \(\frac {-\frac {3 \sqrt {\left (a d -b c \right ) b}\, \left (\left (-b^{4} x^{4}-\frac {14}{3} a \,b^{3} x^{3}+\frac {128}{15} a^{2} b^{2} x^{2}+\frac {14}{3} a^{3} b x +a^{4}\right ) d^{4}+\frac {2 b c \left (b^{3} x^{3}-\frac {233}{5} a \,b^{2} x^{2}+\frac {23}{5} a^{2} b x +a^{3}\right ) d^{3}}{3}+\frac {8 b^{2} c^{2} \left (31 b^{2} x^{2}-64 a b x +a^{2}\right ) d^{2}}{15}-\frac {176 b^{3} c^{3} \left (-\frac {21 b x}{11}+a \right ) d}{15}+\frac {128 b^{4} c^{4}}{15}\right ) \sqrt {d x +c}}{128}+\frac {3 d^{5} \left (b x +a \right )^{5} \arctan \left (\frac {b \sqrt {d x +c}}{\sqrt {\left (a d -b c \right ) b}}\right )}{128}}{\sqrt {\left (a d -b c \right ) b}\, \left (b x +a \right )^{5} \left (a d -b c \right )^{2} b^{3}}\) | \(219\) |
[In]
[Out]
Leaf count of result is larger than twice the leaf count of optimal. 662 vs. \(2 (166) = 332\).
Time = 0.27 (sec) , antiderivative size = 1337, normalized size of antiderivative = 6.75 \[ \int \frac {(c+d x)^{5/2}}{(a+b x)^6} \, dx=\text {Too large to display} \]
[In]
[Out]
Timed out. \[ \int \frac {(c+d x)^{5/2}}{(a+b x)^6} \, dx=\text {Timed out} \]
[In]
[Out]
Exception generated. \[ \int \frac {(c+d x)^{5/2}}{(a+b x)^6} \, dx=\text {Exception raised: ValueError} \]
[In]
[Out]
Leaf count of result is larger than twice the leaf count of optimal. 380 vs. \(2 (166) = 332\).
Time = 0.33 (sec) , antiderivative size = 380, normalized size of antiderivative = 1.92 \[ \int \frac {(c+d x)^{5/2}}{(a+b x)^6} \, dx=\frac {3 \, d^{5} \arctan \left (\frac {\sqrt {d x + c} b}{\sqrt {-b^{2} c + a b d}}\right )}{128 \, {\left (b^{5} c^{2} - 2 \, a b^{4} c d + a^{2} b^{3} d^{2}\right )} \sqrt {-b^{2} c + a b d}} + \frac {15 \, {\left (d x + c\right )}^{\frac {9}{2}} b^{4} d^{5} - 70 \, {\left (d x + c\right )}^{\frac {7}{2}} b^{4} c d^{5} - 128 \, {\left (d x + c\right )}^{\frac {5}{2}} b^{4} c^{2} d^{5} + 70 \, {\left (d x + c\right )}^{\frac {3}{2}} b^{4} c^{3} d^{5} - 15 \, \sqrt {d x + c} b^{4} c^{4} d^{5} + 70 \, {\left (d x + c\right )}^{\frac {7}{2}} a b^{3} d^{6} + 256 \, {\left (d x + c\right )}^{\frac {5}{2}} a b^{3} c d^{6} - 210 \, {\left (d x + c\right )}^{\frac {3}{2}} a b^{3} c^{2} d^{6} + 60 \, \sqrt {d x + c} a b^{3} c^{3} d^{6} - 128 \, {\left (d x + c\right )}^{\frac {5}{2}} a^{2} b^{2} d^{7} + 210 \, {\left (d x + c\right )}^{\frac {3}{2}} a^{2} b^{2} c d^{7} - 90 \, \sqrt {d x + c} a^{2} b^{2} c^{2} d^{7} - 70 \, {\left (d x + c\right )}^{\frac {3}{2}} a^{3} b d^{8} + 60 \, \sqrt {d x + c} a^{3} b c d^{8} - 15 \, \sqrt {d x + c} a^{4} d^{9}}{640 \, {\left (b^{5} c^{2} - 2 \, a b^{4} c d + a^{2} b^{3} d^{2}\right )} {\left ({\left (d x + c\right )} b - b c + a d\right )}^{5}} \]
[In]
[Out]
Time = 0.51 (sec) , antiderivative size = 411, normalized size of antiderivative = 2.08 \[ \int \frac {(c+d x)^{5/2}}{(a+b x)^6} \, dx=\frac {3\,d^5\,\mathrm {atan}\left (\frac {\sqrt {b}\,\sqrt {c+d\,x}}{\sqrt {a\,d-b\,c}}\right )}{128\,b^{7/2}\,{\left (a\,d-b\,c\right )}^{5/2}}-\frac {\frac {d^5\,{\left (c+d\,x\right )}^{5/2}}{5\,b}-\frac {7\,d^5\,{\left (c+d\,x\right )}^{7/2}}{64\,\left (a\,d-b\,c\right )}+\frac {3\,d^5\,\sqrt {c+d\,x}\,\left (a^2\,d^2-2\,a\,b\,c\,d+b^2\,c^2\right )}{128\,b^3}+\frac {7\,d^5\,\left (a\,d-b\,c\right )\,{\left (c+d\,x\right )}^{3/2}}{64\,b^2}-\frac {3\,b\,d^5\,{\left (c+d\,x\right )}^{9/2}}{128\,{\left (a\,d-b\,c\right )}^2}}{b^5\,{\left (c+d\,x\right )}^5-{\left (c+d\,x\right )}^2\,\left (-10\,a^3\,b^2\,d^3+30\,a^2\,b^3\,c\,d^2-30\,a\,b^4\,c^2\,d+10\,b^5\,c^3\right )-\left (5\,b^5\,c-5\,a\,b^4\,d\right )\,{\left (c+d\,x\right )}^4+a^5\,d^5-b^5\,c^5+{\left (c+d\,x\right )}^3\,\left (10\,a^2\,b^3\,d^2-20\,a\,b^4\,c\,d+10\,b^5\,c^2\right )+\left (c+d\,x\right )\,\left (5\,a^4\,b\,d^4-20\,a^3\,b^2\,c\,d^3+30\,a^2\,b^3\,c^2\,d^2-20\,a\,b^4\,c^3\,d+5\,b^5\,c^4\right )-10\,a^2\,b^3\,c^3\,d^2+10\,a^3\,b^2\,c^2\,d^3+5\,a\,b^4\,c^4\,d-5\,a^4\,b\,c\,d^4} \]
[In]
[Out]